A 25.5 mL aliquot of HCl (aq)of unknown concentration was titrated with 0.113 M NaOH (aq).It took 51.2 mL of the base to reach the endpoint of the titration.The concentration (M)of the acid was ________.
A)1.02
B)0.114
C)0.454
D)0.113
E)0.227

Question

Quizplus · Accepted Answer

The concentration of the acid can be calculated using the formula M1V1 = M2V2. Here, M1 is the concentration of HCl, V1 is the volume of HCl, M2 is the concentration of NaOH, and V2 is the volume of NaOH. Plugging in the values: M1 * 25.5 mL = 0.113 M * 51.2 mL. Solving for M1 gives 0.227 M.

A 255 ML Aliquot of HCl (Aq)of Unknown Concentration Was Titrated