The molarity (M)of an aqueous solution containing 22.5 g of sucrose (C₁₂H₂₂O₁₁)in 35.5 mL of solution is ________. A)0.0657 B)1.85 × C)1.85 D)2.33 E)0.634

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of sucrose in the solution. We can use the formula:

moles = mass / molar mass

The molar mass of sucrose (C12H22O11) is 342.3 g/mol. Substituting our values, we get:

moles = 22.5 g / 342.3 g/mol
moles = 0.0657 mol

Next, we need to calculate the volume of the solution in liters:

35.5 mL = 35.5 / 1000 L
35.5 mL = 0.0355 L

Finally, we can calculate the molarity using the formula:

M = moles / volume

Substituting our values, we get:

M = 0.0657 mol / 0.0355 L
M = 1.85 M

Therefore, the answer is (C) 1.85.

The Molarity (M)of an Aqueous Solution Containing 22