The molarity (M)of an aqueous solution containing 129 g of glucose (C₆H₁₂O₆)in 200 mL of solution is ________. A)0.716 B)0.0036 C)3.58 D)0.645 E)645

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of glucose in 129 g:
Molar mass of glucose (C6H12O6) = 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol
Number of moles of glucose = mass/molar mass = 129/180.18 = 0.716 mol

Next, we need to calculate the molarity using the formula:
Molarity = number of moles of solute/volume of solution in liters
Volume of solution in liters = 200 mL/1000 = 0.2 L
Molarity = 0.716 mol/0.2 L = 3.58 M

Therefore, the answer is C, 3.58.

The Molarity (M)of an Aqueous Solution Containing 129 G of Glucose