The molarity of a solution prepared by diluting 43.72 mL of 1.005 M aqueous K₂Cr₂O₇ to 500.mL is ________. A)0.0879 B)87.9 C)0.0218 D)0.0115 E)0.870

Question

Quizplus · Accepted Answer

The molarity (M) of a solution after dilution can be calculated using the formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial solution, and M2 and V2 are the molarity and volume of the final solution. Given M1 = 1.005 M and V1 = 43.72 mL, and V2 = 500 mL, we find M2 by rearranging the formula to M2 = (M1V1) / V2 = (1.005 M * 43.72 mL) / 500 mL = 0.0879 M.

The Molarity of a Solution Prepared by Diluting 43