How many grams of potassium bromide are there in 250.0 mL of a 2.50 M aqueous solution of potassium bromide? A)0.625 B)298 C)74.4 D)1.19 × 10³ E)119

Question

Quizplus · Accepted Answer

We can use the formula:

moles of solute = concentration x volume

First, let's convert the volume from mL to L:

250.0 mL = 250.0/1000 L = 0.250 L

Now we can plug in the values and solve for moles of potassium bromide:

moles of KBr = 2.50 M x 0.250 L = 0.625 moles

Finally, we can convert moles to grams using the molar mass of potassium bromide:

grams of KBr = moles of KBr x molar mass of KBr

The molar mass of KBr is approximately 119 g/mol. So:

grams of KBr = 0.625 moles x 119 g/mol = 74.4 g

Therefore, the answer is C: 74.4.

How Many Grams of Potassium Bromide Are There in 250