The molarity of an aqueous solution containing 75.3 g of glucose (C₆H₁₂O₆)in 35.5 mL of solution is ________. A)14.8 B)2.12 C)481 D)0.0118 E)11.8

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Quizplus · Accepted Answer

To find molarity, divide moles of solute by liters of solution. Molar mass of glucose is 180.18 g/mol. Moles of glucose = 75.3 g / 180.18 g/mol = 0.418 mol. Convert 35.5 mL to liters: 35.5 mL = 0.0355 L. Molarity = 0.418 mol / 0.0355 L = 11.8 M.

The Molarity of an Aqueous Solution Containing 75