What is the mole fraction of I₂ in a solution made by dissolving 55.6 g of I₂ in 245 g of hexane,C₆H₁₄? A)0.0715 B)0.0770 C)0.133 D)0.154

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The mole fraction of a component in a solution is calculated by dividing the moles of that component by the total moles of all components in the solution. First, we need to calculate the moles of I₂ and hexane (C₆H₁₄).- The molar mass of I₂ (I2) is approximately 253.8 g/mol (126.9 g/mol * 2).- The molar mass of hexane (C6H14) is approximately 86.18 g/mol (12.01 g/mol * 6 + 1.008 g/mol * 14).Moles of I₂ = 55.6 g / 253.8 g/mol = 0.219 moles.Moles of hexane = 245 g / 86.18 g/mol = 2.84 moles.Total moles = 0.219 moles + 2.84 moles = 3.059 moles.Mole fraction of I₂ = 0.219 moles / 3.059 moles = 0.0715.

What Is the Mole Fraction of I2 in a Solution

What Is the Mole Fraction of I₂ in a Solution