How many grams of KBr are required to make 350.mL of a 0.115 mol L^-1 KBr aqueous solution? A)0.338 g B)3.04 g C)4.79 g D)40.3 g

Question

Quizplus · Accepted Answer

To calculate the mass of KBr required, we need to use the formula: mass = moles x molar mass where moles = volume x concentration Concentration is given as 0.115 mol L^-1 KBr per liter of solution. So, for 350 mL of solution, the moles of KBr required are: moles = (0.350 L) x (0.115 mol L^-1 KBr per liter) moles = 0.04025 mol L^-1 KBr The molar mass of KBr is 119 g/mol. Using this value, we can calculate the mass of KBr required: mass = (0.04025 mol) x (119 g/mol) mass = 4.79 g Therefore, the correct answer is C) 4.79 g.

How Many Grams of KBr Are Required to Make 350