What molality of pentane is obtained by dissolving 15 g pentane,C₅H₁₂,in 245.0 g hexane,C₆H₁₄? A)0.058 mol kg^-1 B)0.068 mol kg^-1 C)0.85 mol kg^-1 D)61 mol kg^-1

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Quizplus · Accepted Answer

Molality is calculated by dividing the moles of solute by the mass of solvent in kg. Moles of pentane = 15 g / 72.15 g/mol = 0.208 mol. Mass of hexane = 245 g = 0.245 kg. Molality = 0.208 mol / 0.245 kg = 0.85 mol/kg.

What Molality of Pentane Is Obtained by Dissolving 15 G