An RLC series circuit has a 400 $\Omega$ resistance,a 2.5 mH inductor,and a capacitor.If the circuit is in resonance at 30 kHz and is attached to a 20 mV rms power supply,what is the power dissipated by the circuit?
A) 1.0 $\mu$W
B) 2.0 $\mu$W
C) 24 mW
D) 1.2 $\mu$W
E) 1.2 mW

Question

Quizplus · Accepted Answer

The power dissipated by the circuit is given by P = V^2 / R, where V is the rms voltage across the resistor and R is the resistance. At resonance, the voltage across the resistor is equal to the voltage across the power supply, so V = 20 mV. Therefore, P = (20 mV)^2 / 400 $\varOmega$ = 1.0 $\mu$W.

An RLC Series Circuit Has a 400 Ω\OmegaΩ Resistance,a 2 μ\muμ W B) 2

An RLC Series Circuit Has a 400 $\Omega$ Resistance,a 2 $\mu$ W
B) 2