An RLC series circuit has a 400 $\Omega$resistance, a 2.5 mH inductor,and a capacitor.If the circuit is in resonance at 30 kHz and is attached to a 20 mV rms power supply,what is the rms voltage across the inductor?
A) 20 mV
B) 24 mV
C) 16 mV
D) 48 mV
E) 0.00

Question

Quizplus · Accepted Answer

At resonance, the reactances of the inductor and capacitor cancel each other out, leaving only the resistance in the circuit. Therefore, the impedance of the circuit can be calculated as Z = R = 400 Ω.

The rms current through the circuit can be found using the power supply voltage and the impedance:

Irms = Vrms / Z = (20 mV rms) / (400 Ω) = 50 μA rms

Since the inductor is in series with the circuit, the current through it is the same as the total current: Iind = Irms = 50 μA rms.

The rms voltage across the inductor can be calculated using the inductive reactance and the current:

Vind,rms = XL * Iind = (2πfL) * Iind = (2π*30 kHz*2.5 mH) * (50 μA) = 0.024 V rms = 24 mV rms

Therefore, the answer is B) 24 mV.

An RLC Series Circuit Has a 400 Ω\OmegaΩ Resistance, a 2

An RLC Series Circuit Has a 400 $\Omega$ Resistance, a 2