A series RLC circuit has a resistance of 500 $\Omega$, and inductance of 20.0 mH,and a capacitance of 2.00 $\mu$F. The power source provides a voltage of v = (170 sin(377t))V. What is the impedance of this circuit?
A) 0.402 k $\Omega$
B) 1.33 k $\Omega$
C) 1.25 k $\Omega$
D) 1.41 k $\Omega$
E) 2.15 k $\Omega$

Question

Quizplus · Accepted Answer

The impedance of the circuit can be found using the formula: 
Z = √(R^2 + (ωL - 1/(ωC))^2)
where R is the resistance, L is the inductance, C is the capacitance, and ω is the angular frequency (ω = 2πf) of the voltage source. 
Plugging in the given values, we get:
Z = √(500^2 + (2π*60*0.02 - 1/(2π*60*0.000002))^2) 
Z = √(250000 + 2043.88^2) 
Z ≈ 1410 Ω 
Therefore, the answer is D) 1.41 kΩ.

A Series RLC Circuit Has a Resistance of 500 Ω\OmegaΩ , and Inductance of 20

A Series RLC Circuit Has a Resistance of 500 $\Omega$ , and Inductance of 20