# Quiz 24: Photon Dosimetry Concepts and Calculations

Nursing

Q 1Q 1

All of the following apply to "absorbed dose" except:
A) energy deposited at a point
B) measured in Gray
C) measured in air
D) can measure absorbed dose using ionization chambers

Free

Multiple Choice

B One Gray equals 1 Joule/kg.

Q 2Q 2

Dmax is defined as:
A) build-up region
B) depth of maximum equilibrium of occurs for photon beams
C) depth of dose deposited per unit of time
D) dose scatter to surface

Free

Multiple Choice

B Depth of maximum equilibrium,known as Dmax,is where the maximum dose is deposited for that beam.

Q 3Q 3

Mayneord F factor is used in:
A) isocentric setups when distance is increased
B) isocentric setups when field size changes
C) SSD setups when field size changes
D) SSD setups when distance increases

Free

Multiple Choice

D Mayneord F factor is a special application of the inverse square law.This factor is applied when there is a change in distance on an SSD setup.

Q 4Q 4

The intensity of a radiation beam is measured at 10.0 mR/hr at a distance of 20 cm.What will be the intensity of this beam at 30.0 cm?
A) 22.5 mR/hr
B) 4.44 mR/hr
C) 6.67 mR/hr
D) 15.0 mR/hr

Free

Multiple Choice

Q 5Q 5

The intensity of a radioactive beam is measured at a distance of 100 cm and found to be 250 mR/min.What will the intensity of this beam be at 105 cm?
A) 226.8 mR/min
B) 238.1 mR/min
C) 262.5 mR/min
D) 275.6 mR/min

Free

Multiple Choice

Q 6Q 6

Absorbed dose at depth x 100% = absorbed dose at Dmax is the definition of:
A) TAR
B) TMR
C) TPR
D) PDD

Free

Multiple Choice

Q 7Q 7

Absorbed dose at a given depth divided by the dose in air dose at a fixed reference is the definition of:
A) TAR
B) TMR
C) TPR
D) PDD

Free

Multiple Choice

Q 8Q 8

A TAR at the depth of Dmax used to correct for scatter of dose is called the _________.
A) scatter-air ratio
B) tissue-phantom ratio
C) backscatter factor
D) Mayneord's F factor

Free

Multiple Choice

Q 9Q 9

As a field size increases from the standard established,the output factor for a treatment machine will _______________.
A) increase
B) decrease
C) remain the same

Free

Multiple Choice

Q 10Q 10

As the field size increases,the PDD:
A) increase
B) decrease
C) remains the same
D) there is no effect

Free

Multiple Choice

Q 11Q 11

As the energy increases,the PDD:
A) increases
B) decreases
C) remains the same
D) there is no effect

Free

Multiple Choice

Q 12Q 12

As the SSD increases,the PDD:
A) increases
B) decreases
C) remains the same
D) there is no effect

Free

Multiple Choice

Q 13Q 13

As the depth increases,the PDD:
A) increases
B) decreases
C) remains the same
D) there is no effect

Free

Multiple Choice

Q 14Q 14

As the field size increases,the TAR:
A) increases
B) decreases
C) remains the same
D) there is no effect

Free

Multiple Choice

Q 15Q 15

As the energy increases,the TAR:
A) increases
B) decreases
C) remains the same
D) shows no effect

Free

Multiple Choice

Q 16Q 16

As the SSD increases,the TAR:
A) increases
B) decreases
C) remains the same
D) shows no effect

Free

Multiple Choice

Q 17Q 17

The equivalent square of rectangular field of 10 x 15 is:
A) 12 x 12
B) 3.6 x 3.6
C) 11.5 x 11.5
D) 13 x 13

Free

Multiple Choice

Q 18Q 18

The equivalent square of rectangular field of 20 x 10
A) 12 x 12
B) 15 x 15
C) 11.5 x 11.5
D) 13.3 x 13.3

Free

Multiple Choice

Q 19Q 19

A wedge filter is used to alter the isodose distribution on an anterior chest field.The MU setting must be ________________ to account for the wedge filter in the field.
A) increased
B) decreased
C) unchanged

Free

Multiple Choice

Q 20Q 20

A tray holding custom blocks is measured as 97 cGy and the dose without the tray is 100 cGy.What is the tray transmission factor?
A) 103
B) 97
C) 100
D) not enough information to determine

Free

Multiple Choice

Q 21Q 21

What is the patient separation if depth from the AP is 9 cm,and depth from PA is 11 cm?
A) 18 cm
B) 19 cm
C) 20 cm
D) 21 cm

Free

Multiple Choice

Q 22Q 22

What is the patient's depth from the AP if the SAD is 100 cm and SSD is 91 cm?
A) 8 cm
B) 9 cm
C) 10 cm
D) 11 cm

Free

Multiple Choice

Q 23Q 23

What is the depth from the PA if the SAD is 100 cm and the SSD is 89 cm?
A) 8 cm
B) 9 cm
C) 10 cm
D) 11 cm

Free

Multiple Choice

Q 24Q 24

Find the PDD at 10 cm of a 6-MV beam of radiation that has a 5 x 5 cm treatment field.
A) 68.0 %
B) 64.1 %
C) 65.1 %
D) 62.8 %

Free

Multiple Choice

Q 25Q 25

Find the PDD at 19 cm of an 18-MV beam of radiation that has a 12 x 12 cm treatment field.
A) 56.0 %
B) 55.6 %
C) 53.7 %
D) 51.7 %

Free

Multiple Choice

Q 26Q 26

Find the PDD at 3.5 cm of an 18-MV beam of radiation that has a 23 x 15 cm treatment field.
A) 99.8 %
B) 98 %
C) 100 %
D) 98.8 %

Free

Multiple Choice

Q 27Q 27

A patient is treated on a 6-MV accelerator; field size is 10 x 12 cm and depth of tumor is 6 cm.What is the PDD?
A) 83.02
B) 83.18
C) 83.0
D) 83.2

Free

Multiple Choice

Q 28Q 28

A patient is treated on a 6-MV machine at 100 cm SSD.The collimator setting is 15 x 15.There is no blocking used for this treatment.The prescription states that a dose of 3000 cGy is to be delivered to a depth of 3 cm in 10 fractions using a posterior treatment field using the nonisocentric method of calculation.The patient central axis separation is 20 cm.What is the MU setting for the treatment? Reference dose rate (RDR)for a 15 cm equivalent square is 0.993 cGy/MU.
A) 315
B) 321
C) 319
D) 317

Free

Multiple Choice

Q 29Q 29

The physician prescribes the AP/PA field to be weighted 3:1 for the posterior field.How much dose is coming from the AP and the PA if total dose prescribed is 200 cGy?
A) AP = 50 cGy,PA = 150 cGy
B) AP = 75 cGy,PA = 125 cGy
C) AP = 150 cGy,PA = 50 cGy
D) AP = 175 cGy,PA = 25 cGy

Free

Multiple Choice

Q 30Q 30

Calculate the PDD of depth (d)if the dose at Dmax is 180 cGy and the dose at d is 127 cGy.
A) 47%
B) 70.6%
C) 56%
D) 75%

Free

Multiple Choice

Q 31Q 31

Calculate the PDD of depth (d)if the dose at D

_{max}is 250 cGy and the dose at d is 231 cGy. A) 70% B) 75% C) 85.2% D) 92.4%Free

Multiple Choice

Q 32Q 32

Using the 6-MV PDD chart,what is the dose at 10 cm if the dose at Dmax is 300 cGy per day on a 6-MV beam for a field size of 15 x 18?
A) 205 cGy
B) 210 cGy
C) 215 cGy
D) 225 cGy

Free

Multiple Choice

Q 33Q 33

A patient is being treated on the 18-MV beam to a PA spine at a depth of 10 cm.The collimator setting is 10 x 13 with no blocks.The dose is 300 cGy per fraction.What is the dose delivered to Dmax?
A) 375 cGy
B) 240 cGy
C) 400 cGy
D) 300 cGy

Free

Multiple Choice

Q 34Q 34

Find the skin gap necessary to match two symmetric ports at midline that are 21 and 37 cm in length.Assume the midline depth is 13 cm and both ports are treated at 100 cm SAD.
A) 1.53
B) 3.6
C) 2.5
D) 3.77

Free

Multiple Choice

Q 35Q 35

A patient is treated using two superiorly/inferiorly adjacent fields.The collimator setting for the superior field is 10 cm wide by 13 cm long.The collimator setting for the inferior field is 20 cm wide by 35 cm long.Both fields are treated at 100 cm SSD.Calculate the gap at the skin surface if the fields abut at a depth of 5 cm.
A) 1.5
B) 1.2
C) 2.0
D) 1.0

Free

Multiple Choice

Q 36Q 36

Adjacent fields that have an overlap at depth due to divergence are called:
A) separated fields
B) abutted fields
C) half beam blocking fields
D) geometric matching

Free

Multiple Choice

Q 37Q 37

According to the text,methods of obtaining dose uniformity across field junctions include: I.dosimetric isodose matching
II)separated fields
III)junction shift
IV)half beam blocking
V)geometric matching
A) I,II,III,and V
B) I,III,IV,and V
C) II,III,IV,and V
D) III,IV,and V

Free

Multiple Choice

Q 38Q 38

A patient is being treated on the 6-MV beam to an opposed lateral whole brain (midline).The collimator setting is 14 x 18 with no blocks.The dose is 4000 cGy/20 fractions.The separation is 22 cm.What is the dose delivered to Dmax?
A) 200 cGy
B) 212 cGy
C) 150 cGy
D) 61.9 cGy

Free

Multiple Choice

Q 39Q 39

A patient is being treated on the 18-MV beam to an AP/PA stomach (midline).The collimator setting is 12 x 12 with no blocks.The dose is 4400 cGy/22 fractions.The separation is 24 cm.The cord is 4 cm from the PA.What is the dose delivered to the spinal cord?
A) 206.4 cGy
B) 180 cGy
C) 220 cGy
D) 133.7 cGy

Free

Multiple Choice