Find the integral.
-$\int \frac{8}{(y-9)^{3}} d y$
A) $\frac{2}{(y-9)^{4}}+C$
B) $\frac{-2}{(y-9)^{4}}+C$
C) $\frac{4}{(y-9)^{2}}+C$
D) $\frac{-4}{(y-9)^{2}}+C$

Name: Find the integral. -$\int \frac{8}{(y-9)^{3}} d y$ A) $\frac{2}{(y-9)^{4}}+C$ B) $\frac{-2}{(y-9)^{4}}+C$ C) $\frac{4}{(y-9)^{2}}+C$ D) $\frac{-4}{(y-9)^{2}}+C$
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The Answer of Find the integral.
-$\int \frac{8}{(y-9)^{3}} d y$
A) $\frac{2}{(y-9)^{4}}+C$
B) $\frac{-2}{(y-9)^{4}}+C$
C) $\frac{4}{(y-9)^{2}}+C$
D) $\frac{-4}{(y-9)^{2}}+C$

Find the Integral ∫8(y−9)3dy\int \frac{8}{(y-9)^{3}} d y∫(y−9)38​dy A) 2(y−9)4+C\frac{2}{(y-9)^{4}}+C(y−9)42​+C B) −2(y−9)4+C\frac{-2}{(y-9)^{4}}+C(y−9)4−2​+C C) 4(y−9)2+C\frac{4}{(y-9)^{2}}+C(y−9)24​+C D) −4(y−9)2+C\frac{-4}{(y-9)^{2}}+C(y−9)2−4​+C

Find the Integral $\int \frac{8}{(y-9)^{3}} d y$ A) $\frac{2}{(y-9)^{4}}+C$ B) $\frac{-2}{(y-9)^{4}}+C$ C) $\frac{4}{(y-9)^{2}}+C$ D) $\frac{-4}{(y-9)^{2}}+C$