Solve the problem.
-Suppose that the acceleration of an object is given by $a(t)=5 t^{2 / 3}+2 e^{-t}$. The velocity of the object at time 0 is $v(0)=5$ and its position at time 0 is $s(0)=-9$. Find $s(t)$.
A) $\frac{9 t^{8 / 3}}{8}+2 e^{-t}+5 t-9$
B) $\frac{9 t^{8 / 3}}{8}+2 e^{-t}+7 t-11$
C) $\frac{200 t^{8 / 3}}{9}+2 e^{-t}+3 t-11$
D) $3 t^{5 / 3}-2 e^{-t}+7$

Question

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The Answer of Solve the problem.
-Suppose that the acceleration of an object is given by $a(t)=5 t^{2 / 3}+2 e^{-t}$. The velocity of the object at time 0 is $v(0)=5$ and its position at time 0 is $s(0)=-9$. Find $s(t)$.
A) $\frac{9 t^{8 / 3}}{8}+2 e^{-t}+5 t-9$
B) $\frac{9 t^{8 / 3}}{8}+2 e^{-t}+7 t-11$
C) $\frac{200 t^{8 / 3}}{9}+2 e^{-t}+3 t-11$
D) $3 t^{5 / 3}-2 e^{-t}+7$

Solve the Problem a(t)=5t2/3+2e−ta(t)=5 t^{2 / 3}+2 e^{-t}a(t)=5t2/3+2e−t the Velocity of the Object at Time 0 Is

Solve the Problem $a(t)=5 t^{2 / 3}+2 e^{-t}$ the Velocity of the Object at Time 0 Is