Find the integral.
-$\int 3(2 t+5)^{3} d t$
A) $\frac{1}{4}(2 t+5)^{4}+C$
B) $\frac{3}{8}(2 t+5)^{4}+C$
C) $\frac{1}{2}(2 t+5)^{4}+C$
D) $\frac{3}{4}(2 t+5)^{4}+C$

Question

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The Answer of Find the integral.
-$\int 3(2 t+5)^{3} d t$
A) $\frac{1}{4}(2 t+5)^{4}+C$
B) $\frac{3}{8}(2 t+5)^{4}+C$
C) $\frac{1}{2}(2 t+5)^{4}+C$
D) $\frac{3}{4}(2 t+5)^{4}+C$

Find the Integral ∫3(2t+5)3dt\int 3(2 t+5)^{3} d t∫3(2t+5)3dt A) 14(2t+5)4+C\frac{1}{4}(2 t+5)^{4}+C41​(2t+5)4+C B) 38(2t+5)4+C\frac{3}{8}(2 t+5)^{4}+C83​(2t+5)4+C

Find the Integral $\int 3(2 t+5)^{3} d t$ A) $\frac{1}{4}(2 t+5)^{4}+C$ B) $\frac{3}{8}(2 t+5)^{4}+C$