Find the derivative.
-$\frac{(4 x-6)(2 x+5)}{4 x-3}$
A) $\frac{96 x^{2}+16 x-144}{(4 x-3)^{2}}$
B) $\frac{96 x^{2}+16 x-144}{4 x-3}$
C) $\frac{32 x^{2}-48 x+96}{4 x-3}$
D) $\frac{32 x^{2}-48 x+96}{(4 x-3)^{2}}$

Question

Quizplus · Accepted Answer

The derivative of a quotient is found using the quotient rule: $(u/v)' = (u'v - uv')/v^2$. Here, $u = (4x-6)(2x+5)$ and $v = 4x-3$. After applying the product rule to $u$ and simplifying, the correct derivative is $\frac{32 x^{2}-48 x+96}{(4 x-3)^{2}}$.

Find the Derivative (4x−6)(2x+5)4x−3\frac{(4 x-6)(2 x+5)}{4 x-3}4x−3(4x−6)(2x+5)​ A) 96x2+16x−144(4x−3)2\frac{96 x^{2}+16 x-144}{(4 x-3)^{2}}(4x−3)296x2+16x−144​

Find the Derivative $\frac{(4 x-6)(2 x+5)}{4 x-3}$ A) $\frac{96 x^{2}+16 x-144}{(4 x-3)^{2}}$