Use the quotient rule to find the derivative.
-$y=\frac{x^{2}+8 x+3}{\sqrt{x}}$
A) $y^{\prime}=\frac{2 x+8}{2 x^{3 / 2}}$
B) $y^{\prime}=\frac{3 x^{2}+8 x-3}{2 x^{3 / 2}}$
C) $y^{\prime}=\frac{2 x+8}{x}$
D) $y^{\prime}=\frac{3 x^{2}+8 x-3}{x}$

Question

Quizplus · Accepted Answer

The Answer of Use the quotient rule to find the derivative.
-$y=\frac{x^{2}+8 x+3}{\sqrt{x}}$
A) $y^{\prime}=\frac{2 x+8}{2 x^{3 / 2}}$
B) $y^{\prime}=\frac{3 x^{2}+8 x-3}{2 x^{3 / 2}}$
C) $y^{\prime}=\frac{2 x+8}{x}$
D) $y^{\prime}=\frac{3 x^{2}+8 x-3}{x}$

Use the Quotient Rule to Find the Derivative y=x2+8x+3xy=\frac{x^{2}+8 x+3}{\sqrt{x}}y=x​x2+8x+3​ A) y′=2x+82x3/2y^{\prime}=\frac{2 x+8}{2 x^{3 / 2}}y′=2x3/22x+8​

Use the Quotient Rule to Find the Derivative $y=\frac{x^{2}+8 x+3}{\sqrt{x}}$ A) $y^{\prime}=\frac{2 x+8}{2 x^{3 / 2}}$