Use the quotient rule to find the derivative.
-$y=\frac{x^{2}+2 x-2}{x^{2}-2 x+2}$
A) $y^{\prime}=\frac{-4 x^{2}-8 x}{\left(x^{2}-2 x+2\right)^{2}}$
B) $y^{\prime}=\frac{-4 x^{2}+8 x}{\left(x^{2}-2 x+2\right)^{2}}$
C) $y^{\prime}=\frac{4 x^{2}+8 x}{\left(x^{2}-2 x+2\right)^{2}}$
D) $y^{\prime}=\frac{4 x^{2}-8 x}{\left(x^{2}-2 x+2\right)^{2}}$

Question

Quizplus · Accepted Answer

The Answer of Use the quotient rule to find the derivative.
-$y=\frac{x^{2}+2 x-2}{x^{2}-2 x+2}$
A) $y^{\prime}=\frac{-4 x^{2}-8 x}{\left(x^{2}-2 x+2\right)^{2}}$
B) $y^{\prime}=\frac{-4 x^{2}+8 x}{\left(x^{2}-2 x+2\right)^{2}}$
C) $y^{\prime}=\frac{4 x^{2}+8 x}{\left(x^{2}-2 x+2\right)^{2}}$
D) $y^{\prime}=\frac{4 x^{2}-8 x}{\left(x^{2}-2 x+2\right)^{2}}$

Use the Quotient Rule to Find the Derivative y=x2+2x−2x2−2x+2y=\frac{x^{2}+2 x-2}{x^{2}-2 x+2}y=x2−2x+2x2+2x−2​

Use the Quotient Rule to Find the Derivative $y=\frac{x^{2}+2 x-2}{x^{2}-2 x+2}$