Given that line-to-ground voltages of $V_{a g}=280 \angle 0^{\circ}, V_{b g}=250 \angle-110^{\circ}$ , and $V_{c g}=290 \angle 130^{\circ}$ volts are applied to a balanced-Y load consisting of $(3+j 4)$ ohms per phase between the source and the load. The load neutral is solidly grounded. Draw the sequence networks and calculate $I_{0}, I_{1}$ , and $I_{2}$ , the sequence components of the line currents. Then calculate the line currents $I_{a}, I_{b}$ , and $I_{c}$ . Also calculate the real and reactive power delivered to the three-phase load.

Question

Given that line-to-ground voltages of

V_{a g}=280 \angle 0^{\circ}, V_{b g}=250 \angle-110^{\circ}

, and

V_{c g}=290 \angle 130^{\circ}

volts are applied to a balanced-Y load consisting of

(3+j 4)

ohms per phase between the source and the load. The load neutral is solidly grounded. Draw the sequence networks and calculate

I_{0}, I_{1}

, and

I_{2}

, the sequence components of the line currents. Then calculate the line currents

I_{a}, I_{b}

, and

I_{c}

. Also calculate the real and reactive power delivered to the three-phase load.

Quizplus · Accepted Answer

The Answer of 
Given that line-to-ground voltages of $V_{a g}=280 \angle 0^{\circ}, V_{b g}=250 \angle-110^{\circ}$, and $V_{c g}=290 \angle 130^{\circ}$ volts are applied to a balanced-Y load consisting of $(3+j 4)$ ohms per phase between the source and the load. The load neutral is solidly grounded. Draw the sequence networks and calculate $I_{0}, I_{1}$, and $I_{2}$, the sequence components of the line currents. Then calculate the line currents $I_{a}, I_{b}$, and $I_{c}$. Also calculate the real and reactive power delivered to the three-phase load.

Given That Line-To-Ground Voltages Of Vag=280∠0∘,Vbg=250∠−110∘V_{a g}=280 \angle 0^{\circ}, V_{b g}=250 \angle-110^{\circ}Vag​=280∠0∘,Vbg​=250∠−110∘

Given That Line-To-Ground Voltages Of $V_{a g}=280 \angle 0^{\circ}, V_{b g}=250 \angle-110^{\circ}$