One line of a three-phase generator is open circuited, while the other two are short-circuited to ground. The line currents are $I_{a}=0, I_{b}=1500 / 90^{\circ}$, and $I_{c}=$ $1500 \angle-30^{\circ}$ A. Find the symmetrical components of these currents. Also find the current into the ground.

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The Answer of One line of a three-phase generator is open circuited, while the other two are short-circuited to ground. The line currents are $I_{a}=0, I_{b}=1500 / 90^{\circ}$, and $I_{c}=$ $1500 \angle-30^{\circ}$ A. Find the symmetrical components of these currents. Also find the current into the ground.

One Line of a Three-Phase Generator Is Open Circuited, While Ia=0,Ib=1500/90∘I_{a}=0, I_{b}=1500 / 90^{\circ}Ia​=0,Ib​=1500/90∘

One Line of a Three-Phase Generator Is Open Circuited, While $I_{a}=0, I_{b}=1500 / 90^{\circ}$