Solve using the addition and multiplication principles.
-$11 a+2 \geq 12 a+12$
A) $\{a \mid a \leq 11\}$
B) $\{a \mid a \leq-10\}$
C) $\{a \mid a \geq 10\}$
D) $\{\mathrm{a} \mid \mathrm{a}11\}$

Question

Solve using the addition and multiplication principles.
-$11 a+2 \geq 12 a+12$
A) $\{a \mid a \leq 11\}$
B) $\{a \mid a \leq-10\}$
C) $\{a \mid a \geq 10\}$
D) $\{\mathrm{a} \mid \mathrm{a}>11\}$

Quizplus · Accepted Answer

To solve the inequality $11a + 2 \geq 12a + 12$, subtract $11a$ from both sides to get $2 \geq a + 12$. Then, subtract $12$ from both sides to get $-10 \geq a$, which means $a \leq -10$.

Solve Using the Addition and Multiplication Principles 11a+2≥12a+1211 a+2 \geq 12 a+1211a+2≥12a+12

Solve Using the Addition and Multiplication Principles $11 a+2 \geq 12 a+12$