Solve Using the Addition and Multiplication Principles $\frac{x}{2}+14 \leq 10$ A) $\{x \mid x<-6\}$

Solve using the addition and multiplication principles.
- $\frac{x}{2}+14 \leq 10$

A) $\{x \mid x<-6\}$
B) $\{x \mid x \leq 6\}$
C) $\{x \mid x \leq-8\}$
D) $\{x \mid x \geq-8\}$