Solve using the multiplication principle. -$\frac{4}{7}-2 x$ A) $\left\{|x| x\frac{4}{7}\right\}$ B) $\left\{x \mid x

Question

Solve using the multiplication principle. -$\frac{4}{7}>-2 x$ A) $\left\{|x| x>\frac{4}{7}\right\}$ B) $\left\{x \mid x<\frac{4}{7}\right\}$ C) $\left\{x \mid x<\frac{2}{7}\right\}$ D) $\left\{x \mid x>-\frac{2}{7}\right\}$

Quizplus · Accepted Answer

To solve the inequality $\frac{4}{7}>-2x$, divide both sides by -2 (remember to flip the inequality sign when dividing by a negative number): $x<-\frac{4}{7} \cdot \frac{1}{-2}$, which simplifies to $x>-\frac{2}{7}$.

Solve Using the Multiplication Principle 47>−2x\frac{4}{7}>-2 x74​>−2x A) {∣x∣x>47}\left\{|x| x>\frac{4}{7}\right\}{∣x∣x>74​} B) {x∣x<47}\left\{x \mid x<\frac{4}{7}\right\}{x∣x<74​}

Solve Using the Multiplication Principle $\frac{4}{7}>-2 x$ A) $\left\{|x| x>\frac{4}{7}\right\}$ B) $\left\{x \mid x<\frac{4}{7}\right\}$