Solve using the multiplication principle. -$-3 b\frac{1}{9}\right\}$ B) $\left\{b \mid b-\frac{1}{9}\right\}$ C) $\left\{b \mid b

Question

Solve using the multiplication principle. -$-3 b<\frac{1}{3}$ A) $\left\{b \mid b>\frac{1}{9}\right\}$ B) $\left\{b \mid b>-\frac{1}{9}\right\}$ C) $\left\{b \mid b<\frac{1}{9}\right\}$ D) $\left\{\right.$ b $\left.\mid b<-\frac{1}{9}\right\}$

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The Answer of Solve using the multiplication principle. -$-3 b<\frac{1}{3}$ A) $\left\{b \mid b>\frac{1}{9}\right\}$ B) $\left\{b \mid b>-\frac{1}{9}\right\}$ C) $\left\{b \mid b<\frac{1}{9}\right\}$ D) $\left\{\right.$ b $\left.\mid b<-\frac{1}{9}\right\}$

Solve Using the Multiplication Principle −3b<13-3 b<\frac{1}{3}−3b<31​ A) {b∣b>19}\left\{b \mid b>\frac{1}{9}\right\}{b∣b>91​} B) {b∣b>−19}\left\{b \mid b>-\frac{1}{9}\right\}{b∣b>−91​}

Solve Using the Multiplication Principle $-3 b<\frac{1}{3}$ A) $\left\{b \mid b>\frac{1}{9}\right\}$ B) $\left\{b \mid b>-\frac{1}{9}\right\}$