Factor by grouping.
-$2 x^{3}-10 x^{2}-3 x+15$
A) $(x+15)\left(x^{2}-10 x-3\right)$
B) $(x-5)\left(2 x^{2}-3\right)$
C) Not possible
D) $(x+5)\left(2 x^{2}-3\right)$

Question

Quizplus · Accepted Answer

Factor by grouping involves rearranging and grouping terms to factor them. Here, group $2x^3 - 10x^2$ and $-3x + 15$. Factor out $2x^2$ from the first group and $-3$ from the second group: $2x^2(x - 5) - 3(x - 5)$. This gives $(x - 5)(2x^2 - 3)$.

Factor by Grouping 2x3−10x2−3x+152 x^{3}-10 x^{2}-3 x+152x3−10x2−3x+15 A) (x+15)(x2−10x−3)(x+15)\left(x^{2}-10 x-3\right)(x+15)(x2−10x−3) B) (x−5)(2x2−3)(x-5)\left(2 x^{2}-3\right)(x−5)(2x2−3)

Factor by Grouping $2 x^{3}-10 x^{2}-3 x+15$ A) $(x+15)\left(x^{2}-10 x-3\right)$ B) $(x-5)\left(2 x^{2}-3\right)$