Factor by grouping.
-$x^{3}+5 x^{2}+3 x+15$
A) $(x+5)\left(x^{2}-3\right)$
B) $(x+5 x)\left(x^{2}+3\right)$
C) $(x-5)\left(x^{3}+3\right)$
D) $(x+5)\left(x^{2}+3\right)$

Question

Quizplus · Accepted Answer

The expression can be grouped as $(x^3 + 5x^2) + (3x + 15)$. Factoring out the common factors gives $x^2(x + 5) + 3(x + 5)$. Factoring out $(x + 5)$ from both terms results in $(x + 5)(x^2 + 3)$.

Factor by Grouping x3+5x2+3x+15x^{3}+5 x^{2}+3 x+15x3+5x2+3x+15 A) (x+5)(x2−3)(x+5)\left(x^{2}-3\right)(x+5)(x2−3) B) (x+5x)(x2+3)(x+5 x)\left(x^{2}+3\right)(x+5x)(x2+3) C) (x−5)(x3+3)(x-5)\left(x^{3}+3\right)(x−5)(x3+3) D) (x+5)(x2+3)(x+5)\left(x^{2}+3\right)(x+5)(x2+3)

Factor by Grouping $x^{3}+5 x^{2}+3 x+15$ A) $(x+5)\left(x^{2}-3\right)$ B) $(x+5 x)\left(x^{2}+3\right)$ C) $(x-5)\left(x^{3}+3\right)$ D) $(x+5)\left(x^{2}+3\right)$