Factor.
-$4 x^{2}-28 x+48$
A) $(4 x-12)(x-4)$
B) $4(x-12)(x+1)$
C) $4(x-3)(x-4)$
D) Prime

Name: Factor. -$4 x^{2}-28 x+48$ A) $(4 x-12)(x-4)$ B) $4(x-12)(x+1)$ C) $4(x-3)(x-4)$ D) Prime
Brand: Quizplus
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Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is 4, to get $4(x^2-7x+12)$. Then, find factors of 12 that add up to -7, which are -3 and -4. So, the factored form is $4(x-3)(x-4)$.

Factor - 4x2−28x+484 x^{2}-28 x+484x2−28x+48 A) (4x−12)(x−4)(4 x-12)(x-4)(4x−12)(x−4) B) 4(x−12)(x+1)4(x-12)(x+1)4(x−12)(x+1) C) 4(x−3)(x−4)4(x-3)(x-4)4(x−3)(x−4) D) Prime

Factor
- $4 x^{2}-28 x+48$ A) $(4 x-12)(x-4)$ B) $4(x-12)(x+1)$ C) $4(x-3)(x-4)$ D) Prime