Given $\mathbf{R}=\left(\begin{array}{cc}-4 & -4 \ 1 & 5\end{array}\right), \mathbf{S}=\left(\begin{array}{cc}1 & -5 \ -2 & 7\end{array}\right), \vec{u}=(1,1)$, and $\vec{v}=(5,2)$, does $(\vec{u} \cdot \vec{v})(\mathbf{R}+\mathbf{S})=\left(\begin{array}{cc}-3 & -9 \ -5 & 24\end{array}\right) ?$

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The Answer of Given $\mathbf{R}=\left(\begin{array}{cc}-4 & -4 \ 1 & 5\end{array}\right), \mathbf{S}=\left(\begin{array}{cc}1 & -5 \ -2 & 7\end{array}\right), \vec{u}=(1,1)$, and $\vec{v}=(5,2)$, does $(\vec{u} \cdot \vec{v})(\mathbf{R}+\mathbf{S})=\left(\begin{array}{cc}-3 & -9 \ -5 & 24\end{array}\right) ?$

Given , And v⃗=(5,2)\vec{v}=(5,2)v=(5,2) , Does (u⃗⋅v⃗)(R+S)=(−3−9−524)?(\vec{u} \cdot \vec{v})(\mathbf{R}+\mathbf{S})=\left(\begin{array}{cc}-3 & -9 \\ -5 & 24\end{array}\right) ?(u⋅v)(R+S)=(−3−5​−924​)?

Given , And $\vec{v}=(5,2)$ , Does $(\vec{u} \cdot \vec{v})(\mathbf{R}+\mathbf{S})=\left(\begin{array}{cc}-3 & -9 \\ -5 & 24\end{array}\right) ?$