Given $\mathbf{R}=\left(\begin{array}{cc}-3 & -4 \ 1 & 5\end{array}\right), \mathbf{S}=\left(\begin{array}{cc}1 & 3 \ -2 & 7\end{array}\right)$, and $\vec{v}=(-1,2)$ what is $(\mathbf{R}-\mathbf{S}) \vec{v}$ ?

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The Answer of Given $\mathbf{R}=\left(\begin{array}{cc}-3 & -4 \ 1 & 5\end{array}\right), \mathbf{S}=\left(\begin{array}{cc}1 & 3 \ -2 & 7\end{array}\right)$, and $\vec{v}=(-1,2)$ what is $(\mathbf{R}-\mathbf{S}) \vec{v}$ ?

Given R=(−3−415),S=(13−27)\mathbf{R}=\left(\begin{array}{cc}-3 & -4 \\ 1 & 5\end{array}\right), \mathbf{S}=\left(\begin{array}{cc}1 & 3 \\ -2 & 7\end{array}\right)R=(−31​−45​),S=(1−2​37​)

Given $\mathbf{R}=\left(\begin{array}{cc}-3 & -4 \\ 1 & 5\end{array}\right), \mathbf{S}=\left(\begin{array}{cc}1 & 3 \\ -2 & 7\end{array}\right)$