Given $\mathbf{R}=\left(\begin{array}{cc}1 & -4 \ 1 & 5\end{array}\right)$ and $\vec{u}=(1,-4)$, does $\mathbf{R} \vec{u}=(17,-19)$ ?

Name: Given $\mathbf{R}=\left(\begin{array}{cc}1 & -4 \\ 1 & 5\end{array}\right)$ and $\vec{u}=(1,-4)$, does $\mathbf{R} \vec{u}=(17,-19)$ ?
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The Answer of Given $\mathbf{R}=\left(\begin{array}{cc}1 & -4 \ 1 & 5\end{array}\right)$ and $\vec{u}=(1,-4)$, does $\mathbf{R} \vec{u}=(17,-19)$ ?

Given R=(1−415)\mathbf{R}=\left(\begin{array}{cc}1 & -4 \\ 1 & 5\end{array}\right)R=(11​−45​) And u⃗=(1,−4)\vec{u}=(1,-4)u=(1,−4) , Does Ru⃗=(17,−19)\mathbf{R} \vec{u}=(17,-19)Ru=(17,−19)

Given $\mathbf{R}=\left(\begin{array}{cc}1 & -4 \\ 1 & 5\end{array}\right)$ And $\vec{u}=(1,-4)$ , Does $\mathbf{R} \vec{u}=(17,-19)$