Charles's law states that the volume $\mathrm{V}$ of a gas varies directly as its temperature $\mathrm{T}$ in kelvin, provided that the pressure and mass of the gas remains constant. (To convert a Celsius temperature to a kelvin temperature, add 273.) A container of gas has a volume of 450 milliliters at $8^{\circ} \mathrm{C}$. If the gas is cooled and now has a volume of 390 milliliters, what is its temperature in degrees Celsius? Round your answer to the nearest hundredth of a degree as needed.
A) $276^{\circ} \mathrm{C}$
B) $-29.47^{\circ} \mathrm{C}$
C) $265.13^{\circ} \mathrm{C}$
D) $6.5^{\circ} \mathrm{C}$

Question

Quizplus · Accepted Answer

Charles's law can be represented as $V_1/T_1 = V_2/T_2$, where $V$ is volume and $T$ is temperature in kelvins. Convert initial temperature to kelvin: $8^{\circ}C + 273 = 281K$. Using the given volumes, $450/281 = 390/T_2$. Solving for $T_2$ gives $T_2 = 243.53K$, which converts back to $-29.47^{\circ}C$.

Charles's Law States That the Volume V\mathrm{V}V Of a Gas Varies Directly as Its Temperature

Charles's Law States That the Volume $\mathrm{V}$ Of a Gas Varies Directly as Its Temperature