Charles's law states that the volume $V$ of a gas varies directly as its temperature $T$ in kelvin, provided that the pressure and mass of the gas remains constant. (To convert a Celsius temperature to a kelvin temperature, add 273.) A container of gas has a volume of 2.2 liters at $24^{\circ} \mathrm{C}$. If the gas is heated to $49^{\circ} \mathrm{C}$, what will its volume be? Round your answer to the nearest hundredth of a liter as needed.
A) 2.58 liters
B) 4.02 liters
C) 2.39 liters
D) 4.49 liters

Question

Quizplus · Accepted Answer

Charles's law can be represented by the equation $V_1/T_1 = V_2/T_2$, where $V$ is volume, $T$ is temperature in kelvin, and subscripts 1 and 2 refer to the initial and final states, respectively. Convert temperatures to kelvin: $24^{\circ}C + 273 = 297K$ and $49^{\circ}C + 273 = 322K$. Using the given initial volume of 2.2 liters, solve for $V_2$: $2.2/297 = V_2/322$. Solving for $V_2$ gives approximately 2.39 liters.

Charles's Law States That the Volume VVV Of a Gas Varies Directly as Its Temperature

Charles's Law States That the Volume $V$ Of a Gas Varies Directly as Its Temperature