If a projectile is launched straight upward from the ground with an initial velocity of v0 (in feet/second), then the height
(in feet) of the projectile after t seconds is given by the expression -16t2 + v0t. Find the height of the projectile (in feet)
that was launched with the given initial velocity after t seconds.
-94 feet/second, 3.1 seconds
A) 853.74 feet
B) 241.8 feet
C) 143.6 feet
D) 137.64 feet

Question

Quizplus · Accepted Answer

The height is calculated using the formula: -16t^2 + v0t. Substituting v0 = 94 and t = 3.1, we get: -16(3.1)^2 + 94(3.1) = 137.64 feet.

If a Projectile Is Launched Straight Upward from the Ground