If a projectile is launched straight upward from the ground with an initial velocity of v0 (in feet/second), then the height
(in feet) of the projectile after t seconds is given by the expression -16t2 + v0t. Find the height of the projectile (in feet)
that was launched with the given initial velocity after t seconds.
-150 feet/second, 7 seconds
A) 38 feet
B) 266 feet
C) 938 feet
D) 1834 feet

Question

Quizplus · Accepted Answer

The height of the projectile after 7 seconds can be calculated using the given formula: height = -16t^2 + v0t. Substituting v0 = 150 feet/second and t = 7 seconds, we get height = -16(7)^2 + 150(7) = -16(49) + 1050 = -784 + 1050 = 266 feet.

If a Projectile Is Launched Straight Upward from the Ground