If a projectile is launched straight upward from the ground with an initial velocity of v0 (in feet/second) , then the height
(in feet) of the projectile after t seconds is given by the expression -16t2 + v0t. Find the height of the projectile (in feet)
that was launched with the given initial velocity after t seconds.
-63.2 feet/second, 2 seconds
A) 94.4 feet
B) 190.4 feet
C) 62.4 feet
D) 31.2 feet
Correct Answer:
Verified
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