Consider the one-to-one function $f ( x ) = \frac { 1 - x } { 1 + x }$ . Then $f ^ { - 1 } ( x )$ is

A) $\frac { 1 - x } { 1 + x }$
B) $\frac { x - 1 } { x + 1 }$
C) $\frac { 1 + x } { 1 - x }$
D) $\frac { 1 + x } { x - 1 }$
E) $\frac { 1 + \frac { 1 } { x } } { x - 1 }$

Question

Consider the one-to-one function $f ( x ) = \frac { 1 - x } { 1 + x }$ . Then $f ^ { - 1 } ( x )$ is

A) $\frac { 1 - x } { 1 + x }$
B) $\frac { x - 1 } { x + 1 }$
C) $\frac { 1 + x } { 1 - x }$
D) $\frac { 1 + x } { x - 1 }$
E) $\frac { 1 + \frac { 1 } { x } } { x - 1 }$

Quizplus · Accepted Answer

The Answer of Consider the one-to-one function $f ( x ) = \frac { 1 - x } { 1 + x }$ . Then $f ^ { - 1 } ( x )$ is

A) $\frac { 1 - x } { 1 + x }$
B) $\frac { x - 1 } { x + 1 }$
C) $\frac { 1 + x } { 1 - x }$
D) $\frac { 1 + x } { x - 1 }$
E) $\frac { 1 + \frac { 1 } { x } } { x - 1 }$

Consider the One-To-One Function f(x)=1−x1+xf ( x ) = \frac { 1 - x } { 1 + x }f(x)=1+x1−x​

Consider the One-To-One Function $f ( x ) = \frac { 1 - x } { 1 + x }$