Consider the one-to-one function $f ( x ) = 4 + \sqrt [ 3 ] { x - 7 }$ . Then $f ^ { - 1 } ( x )$ is

A) $( x + 7 ) ^ { 3 } - 4$
B) $( x - 4 ) ^ { 3 } - 7$
C) $( x - 7 ) ^ { 3 } + 4$
D) $( x + 4 ) ^ { 3 } - 7$
E) $( x - 4 ) ^ { 3 } + 7$

Question

Consider the one-to-one function $f ( x ) = 4 + \sqrt [ 3 ] { x - 7 }$ . Then $f ^ { - 1 } ( x )$ is

A) $( x + 7 ) ^ { 3 } - 4$
B) $( x - 4 ) ^ { 3 } - 7$
C) $( x - 7 ) ^ { 3 } + 4$
D) $( x + 4 ) ^ { 3 } - 7$
E) $( x - 4 ) ^ { 3 } + 7$

Quizplus · Accepted Answer

The Answer of Consider the one-to-one function $f ( x ) = 4 + \sqrt [ 3 ] { x - 7 }$ . Then $f ^ { - 1 } ( x )$ is

A) $( x + 7 ) ^ { 3 } - 4$
B) $( x - 4 ) ^ { 3 } - 7$
C) $( x - 7 ) ^ { 3 } + 4$
D) $( x + 4 ) ^ { 3 } - 7$
E) $( x - 4 ) ^ { 3 } + 7$

Consider the One-To-One Function f(x)=4+x−73f ( x ) = 4 + \sqrt [ 3 ] { x - 7 }f(x)=4+3x−7​