Consider the one-to-one function $f ( x ) = \sqrt [ 3 ] { 2 x + 3 }$ . Then $f ^ { - 1 } ( x )$ is

A) $\left( \frac { x } { 2 } - 3 \right) ^ { 3 }$
B) $\left( \frac { x - 3 } { 2 } \right) ^ { 3 }$
C) $\frac { x ^ { 3 } - 3 } { 2 }$
D) $\left( \frac { x } { 2 } + 3 \right) ^ { 3 }$
E) $2 x ^ { 3 } - 3$

Question

Consider the one-to-one function $f ( x ) = \sqrt [ 3 ] { 2 x + 3 }$ . Then $f ^ { - 1 } ( x )$ is

A) $\left( \frac { x } { 2 } - 3 \right) ^ { 3 }$
B) $\left( \frac { x - 3 } { 2 } \right) ^ { 3 }$
C) $\frac { x ^ { 3 } - 3 } { 2 }$
D) $\left( \frac { x } { 2 } + 3 \right) ^ { 3 }$
E) $2 x ^ { 3 } - 3$

Quizplus · Accepted Answer

The Answer of Consider the one-to-one function $f ( x ) = \sqrt [ 3 ] { 2 x + 3 }$ . Then $f ^ { - 1 } ( x )$ is

A) $\left( \frac { x } { 2 } - 3 \right) ^ { 3 }$
B) $\left( \frac { x - 3 } { 2 } \right) ^ { 3 }$
C) $\frac { x ^ { 3 } - 3 } { 2 }$
D) $\left( \frac { x } { 2 } + 3 \right) ^ { 3 }$
E) $2 x ^ { 3 } - 3$

Consider the One-To-One Function f(x)=2x+33f ( x ) = \sqrt [ 3 ] { 2 x + 3 }f(x)=32x+3​

Consider the One-To-One Function $f ( x ) = \sqrt [ 3 ] { 2 x + 3 }$