Solve the system of linear equations below by the method of elimination, if a single solution exists. $\left\{ \begin{array} { l }
- 4 x + y = - 4 \
12 x - 3 y = 3
\end{array} \right.$
A) $x = 8 \text { and } y = - 8$
B) $x = 1 \text { and } y = 0$
C) $x = 9 \text { and } y = 4$
D) $x = - 4 \text { and } y = 0$
E)no solution

Question

Solve the system of linear equations below by the method of elimination, if a single solution exists. $\left\{ \begin{array} { l } 
- 4 x + y = - 4 \
12 x - 3 y = 3
\end{array} \right.$
A) $x = 8 \text { and } y = - 8$
B) $x = 1 \text { and } y = 0$
C) $x = 9 \text { and } y = 4$
D) $x = - 4 \text { and } y = 0$
E)no solution

Quizplus · Accepted Answer

The Answer of Solve the system of linear equations below by the method of elimination, if a single solution exists. $\left\{ \begin{array} { l } 
- 4 x + y = - 4 \
12 x - 3 y = 3
\end{array} \right.$
A) $x = 8 \text { and } y = - 8$
B) $x = 1 \text { and } y = 0$
C) $x = 9 \text { and } y = 4$
D) $x = - 4 \text { and } y = 0$
E)no solution

Solve the System of Linear Equations Below by the Method {−4x+y=−412x−3y=3\left\{ \begin{array} { l } - 4 x + y = - 4 \\12 x - 3 y = 3\end{array} \right.{−4x+y=−412x−3y=3​

Solve the System of Linear Equations Below by the Method $\left\{ \begin{array} { l } - 4 x + y = - 4 \\12 x - 3 y = 3\end{array} \right.$