Solve the system of linear equations below by the method of elimination. $\left\{ \begin{array} { c }
4 r - 5 s = 5 \
2 r - 5 s = 15
\end{array} \right.$
A) $r = 9 \text { and } s = - 9$
B) $r = - 1 \text { and } s = - 3$
C) $r = - 8 \text { and } s = - 8$
D) $r = - 5 \text { and } s = - 5$
E) $r = 2 \text { and } s = 4$

Question

Solve the system of linear equations below by the method of elimination. $\left\{ \begin{array} { c } 
4 r - 5 s = 5 \
2 r - 5 s = 15
\end{array} \right.$
A) $r = 9 \text { and } s = - 9$
B) $r = - 1 \text { and } s = - 3$
C) $r = - 8 \text { and } s = - 8$
D) $r = - 5 \text { and } s = - 5$
E) $r = 2 \text { and } s = 4$

Quizplus · Accepted Answer

The Answer of Solve the system of linear equations below by the method of elimination. $\left\{ \begin{array} { c } 
4 r - 5 s = 5 \
2 r - 5 s = 15
\end{array} \right.$
A) $r = 9 \text { and } s = - 9$
B) $r = - 1 \text { and } s = - 3$
C) $r = - 8 \text { and } s = - 8$
D) $r = - 5 \text { and } s = - 5$
E) $r = 2 \text { and } s = 4$

Solve the System of Linear Equations Below by the Method {4r−5s=52r−5s=15\left\{ \begin{array} { c } 4 r - 5 s = 5 \\2 r - 5 s = 15\end{array} \right.{4r−5s=52r−5s=15​

Solve the System of Linear Equations Below by the Method $\left\{ \begin{array} { c } 4 r - 5 s = 5 \\2 r - 5 s = 15\end{array} \right.$