How many liters of a 34% alcohol solution must be mixed with 84% solution to obtain 16 liters of a 71.5% solution?
A)2 liters of a 34% alcohol solution and 14 liters of 84% alcohol solution is required.
B)10 liters of a 34% alcohol solution and 6 liters of 84% alcohol solution is required.
C)12 liters of a 34% alcohol solution and 4 liters of 84% alcohol solution is required.
D)4 liters of a 34% alcohol solution and 12 liters of 84% alcohol solution is required.
E)6 liters of a 34% alcohol solution and 10 liters of 84% alcohol solution is required.

Question

Quizplus · Accepted Answer

To solve this, we can use the equation for mixture problems: (amount of first solution * its percentage + amount of second solution * its percentage) / total amount = desired percentage. Let x be the amount of 34% solution, then (16-x) is the amount of 84% solution. The equation is: (0.34x + 0.84(16-x)) / 16 = 0.715. Solving for x gives x = 4, so 4 liters of 34% solution and 12 liters of 84% solution are needed.

How Many Liters of a 34% Alcohol Solution Must Be