Indicate any inputs that must be excluded and then solve the equation. Factoring of the quadratic equation may be helpful. $$\frac { 9 - x } { x - 3 } = \frac { 6 } { x - 3 }$$
A) $x \neq 0 , x = - 2 , x = 1$
B) $x \neq 0 , x = - 1 , x = 1$
C) $x \neq 3 , x = 1$
D) $x \neq 3 ; x = 0$
E) $x \neq 3 , \text { no solution }$

Question

Quizplus · Accepted Answer

The input $x = 3$ must be excluded because it makes the denominator zero. After canceling the common factor $x - 3$, the equation becomes $9 - x = 6$, which simplifies to $x = 3$. Since $x = 3$ is excluded, there is no solution.

Indicate Any Inputs That Must Be Excluded and Then Solve 9−xx−3=6x−3\frac { 9 - x } { x - 3 } = \frac { 6 } { x - 3 }x−39−x​=x−36​

Indicate Any Inputs That Must Be Excluded and Then Solve $\frac { 9 - x } { x - 3 } = \frac { 6 } { x - 3 }$