Solve: $$\frac { 3 } { 2 x - 7 } = \frac { 6 } { 3 x + 8 }$$
A) $- \frac { 22 } { 7 }$
B) $\frac { 22 } { 7 }$
C) 22
D) -23
E) 23

Name: Solve: \[\frac { 3 } { 2 x - 7 } = \frac { 6 } { 3 x + 8 }\] A) $- \frac { 22 } { 7 }$ B) $\frac { 22 } { 7 }$ C) 22 D) -23 E) 23
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The Answer of Solve: $$\frac { 3 } { 2 x - 7 } = \frac { 6 } { 3 x + 8 }$$
A) $- \frac { 22 } { 7 }$
B) $\frac { 22 } { 7 }$
C) 22
D) -23
E) 23

Solve 32x−7=63x+8\frac { 3 } { 2 x - 7 } = \frac { 6 } { 3 x + 8 }2x−73​=3x+86​

Solve $\frac { 3 } { 2 x - 7 } = \frac { 6 } { 3 x + 8 }$