Indicate any inputs that must be excluded and then solve the equation. Factoring of the quadratic equation may be helpful. $$x + 3 = \frac { x + 3 } { x }$$
A) $x \neq 0 , x = - 1 , x = 2$
B) $x \neq 0 , x = - 3 , x = 1$
C) $x \neq 0 , x = - 1$
D) $x \neq 0 ; x = 3$
E) $x \neq 0 , \text { no solution }$

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The Answer of Indicate any inputs that must be excluded and then solve the equation. Factoring of the quadratic equation may be helpful. $$x + 3 = \frac { x + 3 } { x }$$
A) $x \neq 0 , x = - 1 , x = 2$
B) $x \neq 0 , x = - 3 , x = 1$
C) $x \neq 0 , x = - 1$
D) $x \neq 0 ; x = 3$
E) $x \neq 0 , \text { no solution }$

Indicate Any Inputs That Must Be Excluded and Then Solve x+3=x+3xx + 3 = \frac { x + 3 } { x }x+3=xx+3​

Indicate Any Inputs That Must Be Excluded and Then Solve $x + 3 = \frac { x + 3 } { x }$