$E _ { i } = E _ { \max } \sin \theta$ An AC voltage has an instantaneous value of 110 volts. Find to the nearer degree the phase angle if the peak voltage is 155.5 volts.

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The Answer of $E _ { i } = E _ { \max } \sin \theta$ An AC voltage has an instantaneous value of 110 volts. Find to the nearer degree the phase angle if the peak voltage is 155.5 volts.

Ei=Emax⁡sin⁡θE _ { i } = E _ { \max } \sin \thetaEi​=Emax​sinθ

$E _ { i } = E _ { \max } \sin \theta$