$O P = V _ { 1 } ^ { 2 } + V _ { 2 } ^ { 2 } + 2 \left( V _ { 1 } \right) \left( V _ { 2 } \right) \cos \theta$ A transformer secondary circuit is shown. Find $I _ { S }$ . Express the answer to the nearer tenth. Hint: First apply Ohm s law E=IR to find $I _ { H }$ and $I _ { L }$ .

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The Answer of $O P = V _ { 1 } ^ { 2 } + V _ { 2 } ^ { 2 } + 2 \left( V _ { 1 } \right) \left( V _ { 2 } \right) \cos \theta$ A transformer secondary circuit is shown. Find $I _ { S }$ . Express the answer to the nearer tenth. Hint: First apply Ohm s law E=IR to find $I _ { H }$ and $I _ { L }$ .

OP=V12+V22+2(V1)(V2)cos⁡θO P = V _ { 1 } ^ { 2 } + V _ { 2 } ^ { 2 } + 2 \left( V _ { 1 } \right) \left( V _ { 2 } \right) \cos \thetaOP=V12​+V22​+2(V1​)(V2​)cosθ

$O P = V _ { 1 } ^ { 2 } + V _ { 2 } ^ { 2 } + 2 \left( V _ { 1 } \right) \left( V _ { 2 } \right) \cos \theta$