$E _ { i } = E _ { \max } \sin \theta$ Find the phase angle at which an instantaneous voltage of 144 appears in a wave with a peak value of 500 volts. Round the answer to the nearer degree.

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The Answer of $E _ { i } = E _ { \max } \sin \theta$ Find the phase angle at which an instantaneous voltage of 144 appears in a wave with a peak value of 500 volts. Round the answer to the nearer degree.

Ei=Emax⁡sin⁡θE _ { i } = E _ { \max } \sin \thetaEi​=Emax​sinθ

$E _ { i } = E _ { \max } \sin \theta$