Factor the trinomial completely.
-$14 y ^ { 2 } + 63 y - 35$
A)(14y - 7)(y + 5)
B)7(2y - 1)(y + 5)
C)7(2y + 1)(y - 5)
D)prime

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor (GCF), which is 7, to get $7(2y^2 + 9y - 5)$. Then, find two numbers that multiply to $2 \times -5 = -10$ and add to $9$, which are $10$ and $-1$. Use these to split the middle term: $7(2y^2 + 10y - y - 5)$. Factor by grouping: $7((2y^2 + 10y) - (y + 5)) = 7(2y(y + 5) - 1(y + 5)) = 7(2y - 1)(y + 5)$.

Factor the Trinomial Completely 14y2+63y−3514 y ^ { 2 } + 63 y - 3514y2+63y−35

Factor the Trinomial Completely $14 y ^ { 2 } + 63 y - 35$