Factor the trinomial completely.
-$- 64 x ^ { 3 } + 64 x ^ { 2 } + 20 x$
A) $- 4 \left( 4 x ^ { 2 } + 1 \right) ( 4 x - 5 )$
B) $- 4 x ( 4 x + 1 ) ( 4 x - 5 )$
C) $x ( 4 x + 1 ) ( - 16 x + 20 )$
D) $x ( - 16 x - 4 ) ( 4 x - 5 )$

Question

Factor the trinomial completely.
-$- 64 x ^ { 3 } + 64 x ^ { 2 } + 20 x$
A)  $- 4 \left( 4 x ^ { 2 } + 1 \right) ( 4 x - 5 )$
B) $- 4 x ( 4 x + 1 ) ( 4 x - 5 )$
C) $x ( 4 x + 1 ) ( - 16 x + 20 )$
D) $x ( - 16 x - 4 ) ( 4 x - 5 )$

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $4x$, resulting in $4x(-16x^2 + 16x + 5)$. Factoring the quadratic gives $4x(4x + 1)(4x - 5)$.

Factor the Trinomial Completely −64x3+64x2+20x- 64 x ^ { 3 } + 64 x ^ { 2 } + 20 x−64x3+64x2+20x

Factor the Trinomial Completely $- 64 x ^ { 3 } + 64 x ^ { 2 } + 20 x$